2x^-2/3-7x^-1/3+5=0

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Solution for 2x^-2/3-7x^-1/3+5=0 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(2*x^-2)/3-((7*x^-1)/3)+5 = 0

(-7/3)*x^-1+(2*x^-2)/3+5 = 0

2/3*x^-2-7/3*x^-1+5 = 0

t_1 = x^-1

2/3*t_1^2-7/3*t_1^1+5 = 0

2/3*t_1^2-7/3*t_1+5 = 0

DELTA = (-7/3)^2-(2/3*4*5)

DELTA = -71/9

DELTA < 0

x belongs to the empty set

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